15 thoughts on “HOMEWORK 6 - Sp 25”

    1. Hmm, I believe that if I did the right hand rule correctly (hand pointed in direction of position vector, fingers bend towards force tension force vector down towards pt B, thumb pointing up and away from you) the x value component should be negative, and y and z components should be positive regardless of if its for question a or b. Is that what you got?

  1. How does the direction of the tension force in cable AB influence the resulting moment about point O, and how would the moment change if the attachment point A were moved along the bar?

    1. If A is moved along the bar, then the vector AB would be different because the point A has different coordinates. This would then change the unit vector AB which would in turn change the force vector AB. To answer your first question I think the direction of force AB is what decides the direction of the moment (i.e. the signs of the x, y, and z coordinates of the torque about O).

  2. A bit confused on what this Moment about point O actually means. If its torque won't that mean the structure will just fall down? How do I put my answer into like a full sentence?

    1. I just left my answer in terms of i j and k. I think the answer represents the direction the point O wants to move due to the tension force, but it is not moving because it is in static equilibrium due to some other force preventing O from moving.

Leave a Reply